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OpenStudy (anonymous):
one sec let me right it out
OpenStudy (anonymous):
what are the coordinates of the vertex of
f(x)=(2x+1)^2+3
OpenStudy (anonymous):
@iGreen
OpenStudy (anonymous):
please explain how
OpenStudy (igreen):
What?
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OpenStudy (igreen):
What do you mean by 'coordinates'?
OpenStudy (anonymous):
well thats the question so idk
OpenStudy (igreen):
Um, hold on.
OpenStudy (anonymous):
take yah timebro
OpenStudy (igreen):
Do you have choices..?
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OpenStudy (anonymous):
its a dba so one sec i think i figured something out
OpenStudy (anonymous):
vertex: (- 1/2 ,3)
OpenStudy (anonymous):
a=4
h=-1/2
k=3
OpenStudy (igreen):
???
OpenStudy (anonymous):
its fine dude nvm....do you understand it though its 9th grade so
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OpenStudy (igreen):
I don't know what its asking exactly..
OpenStudy (igreen):
Is it asking for the vertex of the parabola?
OpenStudy (anonymous):
irs asking coordinates of vertex
OpenStudy (anonymous):
its
OpenStudy (igreen):
Oh, okay.
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OpenStudy (igreen):
It's in vertex form..
OpenStudy (owlfred):
The vertex always occurs at the maximum or minimum of a parabola. There are many ways to find it. Just for starters, the vertex of \(f(x) = (ax + b)^2 + h\) occurs when \(ax + b\) = 0, and when it is \(0\), then the function would evaluate to \(h\).
OpenStudy (igreen):
\(f(x)=(2x+1)^2+3\)
Vertex form:
\(y = a(x – h)^2 + k
\)
Where vertex = (h, k)
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
would h=-1/2
k=3
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