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How do I find two consecutive integers between which the root of sin x = 1 - x lies?
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@Princer_Jones @iGreen
\[\sqrt{\sin x}=1-x\]like this?
Not quite; it means where sin x = 1 - x crosses the x axis.
I realise I can just substitute numbers in and find the two between which the sign of the function changes, but it there another way to do it/
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graph y= sin x and y = -x + 1 and see where they are equal (intersect)
when graphing sin x , x is in radians
pi/6 is close to 1/2 and sin of pi/6 is 1/2 so I'd say between 0 and 1
Okay, I think I got it. I was wondering I needed to take the derivative or something, but it doesn't seem like it. I also get that the root is between 0 and 1. Thanks!
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