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Chemistry 8 Online
OpenStudy (anonymous):

Help filling in the blanks. Can someone just tell now how they did the first one and ill do the rest thanks

OpenStudy (anonymous):

OpenStudy (anonymous):

@sikinder

OpenStudy (anonymous):

2.)7.5 ,2.5 3)9 , 1 4)8 ,2

OpenStudy (anonymous):

are these correct?

OpenStudy (anonymous):

@sheetalvee

OpenStudy (anonymous):

im not sure, how did you get those ?

OpenStudy (anonymous):

simple its dilution process

OpenStudy (anonymous):

You dilute a solution whenever you add solvent to a solution. Adding solvent results in a solution of lower concentration. You can calculate the concentration of a solution following a dilution by applying this equation: MiVi = MfVf where M is molarity, V is volume, and the subscripts i and f refer to the initial and final values. Example: How many millilieters of 5.5 M NaOH are needed to prepare 300 mL of 1.2 M NaOH? Solution: 5.5 M x V1 = 1.2 M x 0.3 L V1 = 1.2 M x 0.3 L / 5.5 M V1 = 0.065 L V1 = 65 mL So, to prepare the 1.2 M NaOH solution, you pour 65 mL of 5.5 M NaOH into your container and add water to get 300 mL final volume.

OpenStudy (anonymous):

@sheetalvee

OpenStudy (anonymous):

Thanks !

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