Question

@BlackSwordsmanKirito

Answer 1

Here's the question

Answer 2

what grade r u in?

Answer 3

12th lol why? :(

Answer 4

>.> cant help meh bad. im only in the 9th

Answer 5

@Catlover5925

Answer 6

are you in honour math? this question seems challenging

Answer 7

@bibby @jigglypuff314

Answer 8

I'm on the math team, but it's too hard. I did half of it though

Answer 9

i got A=-5, B=-8

Answer 10

same

Answer 11

so answer is 89

Answer 12

i was clueless but thats what i got

Answer 13

bruh i should skip the 9th and 10th grade!!

Answer 14

trust me it's right, i'm #2 in provincial math competition :)

Answer 15

OMG IM A BOSS!!!!

Answer 16

How did you guys get this????

Answer 17

-does the naenae-

Answer 18

blacksword go explain her

Answer 19

@bibby helpppppp meeeeee

Answer 20

i choose my random numbers 1 - 10 and so non of them worked to help compute
so my next step to try was negative 1 - 10

Answer 21

i'm not sure someone of bibby's intellect is capable of doing this

Answer 22

gross. 12th is too old
factor (N-1) out of the numerator and then you'll have something in the form of

\(\huge \frac{(N-1)(x)}{(N-1)(N-2)}\) cancel the n-1s and you'll have the \(\frac{B}{N-2}\)

Answer 23

wowwwwww

Answer 24

constantly going through those i got A = -5, b = -8 which = 89

Answer 25

I might be retarded but I can do high school math

Answer 26

lmaoooooooooo
I'm too old???

Answer 27

0-0 glory destroyer...

Answer 28

pedophilia man
I didn't choose this lifestyle
it chose me

Answer 29

lmaoooooooooooooo

Answer 30

so the answer is 5 and 89 ?

Answer 31

no 89

Answer 32

well yes

Answer 33

@iambatman

Answer 34

well, I got 185

Answer 35

i'm just trolling, this question is cake :)

Answer 36

pls help me @teddyiswhathecallsme

Answer 37

bruh i got math problems

Answer 38

Teddy help!!

Answer 39

answer is 89, rest is up to @bibby

Answer 40

how do you know?? teddy

Answer 41

he's making it up. nobody here can actually help you

Answer 42

ik i cant

Answer 43

i still gave a medal doh

Answer 44

lol i didn't make it up, just too lazy to explain

Answer 45

i think @bibby is having trouble figuring it out

Answer 46

e.e

Answer 47

I am. hehehe is that right so far?
\(\huge \frac{a}{n-1}-\frac{b}{n-2}=\frac{3n+2}{n-1(n-2)}\)
\(\huge \frac{a(n-2)-b(n-1)}{(n-1)(n-2)}=\frac{3n+2}{n-1(n-2)}\)

Answer 48

I honestly dont know what I'm doing

Answer 49

can i get a medal for being in the 9th grade and still helping

Answer 50

shut up ted

Answer 51

XD

Answer 52

write A/(N-1)-B/(N-2) in the form of SOMESH1T/((N-1)(N-2)), the rest is obvious

Answer 53

so no medal?

Answer 54

\(A(N-2)-B(N-1)=3N+2\)
\(A=\frac{3N+2+B(N-1)}{N-2}\)
like that?

Answer 55

no

Answer 56

;-; ur mean teddy

Answer 57

oh nvm

Answer 58

@jdoe0001

Answer 59

k

Answer 60

\(\large {
\cfrac{3N+2}{(N-1)(N-2)}=\cfrac{A}{(N-1)}-\cfrac{B}{(N-2)}
\\ \quad \\

\cfrac{3N+2}{(N-1)(N-2)}\implies
\begin{cases}
\cfrac{3N}{(N-1)(N-2)}\quad +\\
\cfrac{2}{(N-1)(N-2)}\qquad thus


\end{cases}\\ \quad \\
\cfrac{3N+2}{(N-1)(N-2)}\implies \cfrac{3N}{(N-1)(N-2)}\quad +
\cfrac{2}{(N-1)(N-2)}
\\ \quad \\
{\color{brown}{ \cfrac{3N}{(N-1)(N-2)}}}\quad +
\cfrac{2}{(N-1)(N-2)}={\color{brown}{\cfrac{A}{(N-1)}}}-\cfrac{B}{(N-2)}
\\ \quad \\

\begin{cases}
\cfrac{3N}{(N-1)(N-2)}=\cfrac{A}{(N-1)}\implies \cfrac{3N\cancel{ (N-1) }}{\cancel{ (N-1) }(N-2)}=A
\\ \quad \\
\cfrac{2}{(N-1)(N-2)}=-\cfrac{B}{(N-2)}\implies \cfrac{-\cancel{ (N-2) }2}{(N-1)\cancel{ (N-2) }}=B
\end{cases}
}\)

Answer 61

A/(N-1)-B/(N-2) = (A(N-2)-B(N-1))/((N-1)(N-2))
this implies
A(N-2)-B(N-1)=3N+2
(A-B)N+(B-2A)=3N+2

so
A-B=3
B-2A=2

now just solve for A, B

Answer 62

SO EASSSAAAAYYYYYYYYYYYYY

Answer 63

well NOWW it's easy

Answer 64

I need explanations
I'm feeling dumb right now lol