A family of functions is given by
r(x) = 1/[a-(x-b)^2]
Assume a 0, b 0.

Find the vertical asymptotes of
r(x)

Question

A family of functions is given by 
r(x) = 1/[a-(x-b)^2]
Assume a > 0, b > 0. 

Find the vertical asymptotes of 
r(x)

anonymous · Answer

set the denominator equal to zero and solve for $x$

anonymous · Answer

clear or no?

anonymous · Answer

that make sense!

anonymous · Answer

Vertical asymptotes will appear when division by 0 occurs, so that is why you want to find where the denominator is 0.

anonymous · Answer

I can't seem to solve for the denominator to equal 0..

anonymous · Answer

$$
a-(b-x)^2 = a - (b^2-2bx+x^2) = (-1)x^2 +(2b)x+(a-b^2)
$$

anonymous · Answer

it looks like i can somehow use the quadratic formula right..? the answer I am supposed to get is both positive and negative

anonymous · Answer

Yes, the solution must be in terms of a and b.