Consider a curve of the form y(t) = at + (b/t), with a local minimum at (3, 12). (c) find the exact values of a and b that satisfy the conditions in part (a). --> part a: (3,12) tells us that y(3)=12
My professor did not go over this in class so I need to see how this problem is done; I have three other problems on my homework like this problem.
Alright, so this seems doable. So the problem tells us that this function has a local minimum at (3,12). How do we find the local minimum of a function?
You find the 1st derivative of the function, set it equal to zero, and do the first derivative test to see whether its a min or max right..?
Good. And what would the derivative of this function be?
a-(b/t^2)..?
Correct.
Now at a local minimum the derivative equals 0, right?
so how would i find the values of a and b though? :/
yeah!
What we're working towards right now is getting two equations that relate a and b. Then we can use those equations to solve for a and b.
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