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Mathematics 13 Online
OpenStudy (anonymous):

if 3x+2y=1 & 2x+3y=4 then x+y must be?

OpenStudy (immanuelv):

first find x and y by using substitution, subtraction or matrix :)

OpenStudy (anonymous):

i.e. solve for \(x\) and \(y\) then add them you know how to do that?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

you can almost do this one in your head

OpenStudy (anonymous):

ok good let me know what you get

OpenStudy (anonymous):

i get 1@satellite73

OpenStudy (anonymous):

for the sum, yes \[x=-1,y=2,-1+2=1\]

OpenStudy (anonymous):

yes i was getting the same:) ty

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

a circle is tangent to both axis if the distance from the origin to the centree of circle is r what is the area of the circle? @satellite73

OpenStudy (anonymous):

hmm now i have to think, it is geometry

OpenStudy (anonymous):

|dw:1415335913391:dw|

OpenStudy (anonymous):

you wan the radius of the circle, which may or may not be obvious, but it is \[\frac{r}{\sqrt2}\]

OpenStudy (anonymous):

|dw:1415336053989:dw|

OpenStudy (anonymous):

then the area is \[\pi\left(\frac{r}{\sqrt2}\right)^2\]

OpenStudy (anonymous):

why u writ radius of circle as \[r/\sqrt{2}\]

OpenStudy (anonymous):

you got a right triangle there with two 45 degree angles

OpenStudy (anonymous):

that means means the leg of the triangle is \(\frac{r}{\sqrt2}\)

OpenStudy (anonymous):

have you had trig yet, or not we can do it without trig if you like

OpenStudy (anonymous):

it must be than rsqrt2?

OpenStudy (anonymous):

i studied trignometry

OpenStudy (anonymous):

the confusing part is that the radius is not \(r\) it is the leg of the triangle

OpenStudy (anonymous):

|dw:1415336497180:dw|

OpenStudy (anonymous):

but to get the leg, you have to divide the hypotenuse by \(\sqrt2\)

OpenStudy (anonymous):

ok in right angle the hypotnuse is xsqrt2

OpenStudy (anonymous):

right but you have the hypotenuse is r, so the leg is \(\frac{r}{\sqrt2}\)

OpenStudy (anonymous):

|dw:1415336589242:dw|

OpenStudy (anonymous):

it must be then |dw:1415336676855:dw|

OpenStudy (anonymous):

yeah so |dw:1415336670508:dw|

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