if 3x+2y=1 & 2x+3y=4 then x+y must be?
first find x and y by using substitution, subtraction or matrix :)
i.e. solve for \(x\) and \(y\) then add them you know how to do that?
yes
you can almost do this one in your head
ok good let me know what you get
i get 1@satellite73
for the sum, yes \[x=-1,y=2,-1+2=1\]
yes i was getting the same:) ty
yw
a circle is tangent to both axis if the distance from the origin to the centree of circle is r what is the area of the circle? @satellite73
hmm now i have to think, it is geometry
|dw:1415335913391:dw|
you wan the radius of the circle, which may or may not be obvious, but it is \[\frac{r}{\sqrt2}\]
|dw:1415336053989:dw|
then the area is \[\pi\left(\frac{r}{\sqrt2}\right)^2\]
why u writ radius of circle as \[r/\sqrt{2}\]
you got a right triangle there with two 45 degree angles
that means means the leg of the triangle is \(\frac{r}{\sqrt2}\)
have you had trig yet, or not we can do it without trig if you like
it must be than rsqrt2?
i studied trignometry
the confusing part is that the radius is not \(r\) it is the leg of the triangle
|dw:1415336497180:dw|
but to get the leg, you have to divide the hypotenuse by \(\sqrt2\)
ok in right angle the hypotnuse is xsqrt2
right but you have the hypotenuse is r, so the leg is \(\frac{r}{\sqrt2}\)
|dw:1415336589242:dw|
it must be then |dw:1415336676855:dw|
yeah so |dw:1415336670508:dw|
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