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Please integrate cos^2x showing steps :)
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\[\cos^2 x = \frac{1 + \cos(2x)}{2} \]
Yess! I didn't get this part. Cos^2x is equal to that^??
Yes it is. Here is how you derive it.\[\cos^2 x - \sin^2 x = \cos(2x)\]\[\Rightarrow \cos^2 x - (1 - \cos^2 x) = \cos(2x)\]\[\Rightarrow 2\cos^2 x - 1=\cos(2x)\]\[\Rightarrow \cos^2 x = \dfrac{1 + \cos(2x)}{2}\]
Ohhhh
THANK YOUUU :)
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No problem. Welcome back to OS!
Haha, thanks!
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