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Calculus1
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Evaluate: I didnt know how to write it all out up here, so it is down below
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\[\int\limits_{0}^{\pi} (\cos (\theta)^2)^{1/2} d \theta \]
\[put ~\theta^2=t,\theta=\sqrt{t},d \theta=\frac{ 1 }{2\sqrt{t} }dt\] \[when~\theta=0,t=0\] \[when~\theta=\pi,t=\pi^2\] \[I=\int\limits_{0}^{\pi^2} \sqrt{\cos t}*\frac{ 1 }{ 2\sqrt{t} }dt\]
Is that he final answer? I was thinking I had to go farther than that for some reason
yes idiot
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