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Chemistry 11 Online
OpenStudy (anonymous):

In the equation (Cr2O7^2- + 6CH3OH + 8H+ --> 6CH2O + 2Cr^3+ + 7H2O) what is the element being oxidized and what element is being reduced?

OpenStudy (anonymous):

@e.mccormick

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

@uri @cwrw238

OpenStudy (cuanchi):

Cr2O7^2- -> 2Cr^3+ Cr (+6) -> Cr^3+ reduced CH3OH -> 6CH2O C (-2) -> C(+3) oxidized

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