Question

Given that f(x) = x2 − 3x + 3 and g(x) = the quantity of x minus one, over four, solve for f(g(x)) when x = 5.
A) -3
B) 1
C)7
D)13

Answer 1

@johnweldon1993

Answer 2

\[\large f(x) = x^2 - 3x + 3\]
\[\large g(x) = \frac{x - 1}{4}\]

So what we do...is take our inside function *g(x)* and solve it when x = 5

can you do that?

Answer 3

okay so 5-1/4

Answer 4

mmhmm :) which is?

Answer 5

4/4 which is obvisously 1

Answer 6

Indeed...so now..we take that result (1)

and we plug that into f(x) wherever we see an 'x'

\[\large f(1) = 1^2 - 3(1) + 3\]