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Mathematics 11 Online
OpenStudy (jhannybean):

Simplifying \[\-e^{-\ln(x)}\]

OpenStudy (jhannybean):

\[\ -e^{-ln(x)}\]

OpenStudy (johnweldon1993):

Lol oh @Jhannybean look at the message I sent :P \[\large -e^{-\ln(x)} = \frac{1}{-e^{\ln(x)}}\]

OpenStudy (kainui):

\[\LARGE -e^{-lnx}=-e^{\ln(1/x)}=-\frac{1}{x}\] alternatively we can write: \[\LARGE -e^{-lnx}=-(e^{lnx})^{-1}=-x^{-1}\]

OpenStudy (jhannybean):

@johnweldon1993 I understood how you solved this, but i'm just wondering if there was an alternative way by factoring out the negatives

OpenStudy (jhannybean):

Ah ok :) thanks you guys!

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