Question

true or false?

Answer 1

what does a domain tell us?

Answer 2

the base?

Answer 3

the usable inputs. do they both have the same usable x values?

Answer 4

cbrt .... i was reading it as a sqrt. domain and range are fine

Answer 5

huh? I'm confused

Answer 6

and logically speaking, if we have half of something, then we are necessarily shorter/smaller than the original

Answer 7

by convention we do not shrink things horizontally.

if y1 = 1/2 yo then measuring with respect to the y axis ... the shrink is vertical right?

Answer 8

i was worried about A but thats because i read the problem is a squareroot (sqrt) instead of a cuberoot (cbrt). but A is fine

Answer 9

overall, you are correct, A and B are correct

Answer 10

ohhhhhh ok what about c

Answer 11

tell me what your thought are in C ....

Answer 12

sorry I meant d and because it shrinks vertically?

Answer 13

d is comparing an apple to an orange ...

Answer 14

sqrt does not look like cbrt

Answer 15

oh...

Answer 16

A is not correct the first function's domain is {x belongs to R such that x>=2} and the second function's domain is {x belongs to R such that x>=0}

Answer 17

\[f(x)=\sqrt[3]{x}~:~dom(f)=all~Reals\]
shifting it left or right does not affect the domain since there are no restrictions to be had to start with

Answer 18

ok...confused now

Answer 19

IF, like i had read to start with this was:
\[f(x)=\sqrt{x}~:~dom(f)=x\ge0\]
then shifting it would affect the domian

Answer 20

if you are confused, then you simply need to get a better grasp on what a domain and range for a function are. but im thinking you already know it and just lack the confidence. you did fine. A and B are correct

Answer 21

@amistre64 sorry, i thought it is sq root.

Answer 22

i know :) i mistook it as a sqrt to begin with when i asked about domain.

Answer 23

Thank you again @amistre64