The radius of the circle whose equation in parametric form is P(x)= (acosx+bsinx , asinx -bcosx)
so the graph is P(x) = ( acos x + bsin x , a sin x - b cos x )
it probably makes more sense to use 't' as the parameter, but in any case
let me graph it in parametric mode on my calculator
actually it was theta , but i couldn't type the symbol so i used x
im going to use 't' as the parameter , P(t)= (acost+bsint , asint -bcost)
okay
lets represent theta by t then :)
so we have P(t) = (x(t), y(t)) where x(t) = a cos t + b sin t y(t) = a sin t - b cos t first impulse is to square x and y x^2 + y^2 = ( a cos t + b sin t ) ( a sin t - b cost ) = a^2 cos t sin t + a*b sin^t - a*b cos^2 t - b^2 cos t sin t
that should stay a*b sin^2(t)
yes then
i got an idea....
actually lets solve for x^2 separately
x^2 = a^2 cos^2 (t) + b^2 * sin^2(t) + acos(t)*b*sint(t)
|dw:1415490786323:dw| The next thing to do is pretty obvious
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