Find the point on the terminal side of \(\theta~=~-\dfrac{3\pi}{4}\) that has an x coordinate of -1. Show your work.
@Callisto
What is \(\frac{3\pi}{4}\) in degrees?
\(\dfrac{3\pi}{4}*\dfrac{180}{\pi}=\dfrac{540\pi}{4\pi}\pi~cancels\\\dfrac{540}{4}=135\)
Yes. So, \(-\frac{3\pi}{4} \)=-135° Can you locate where -135° is in this drawing? |dw:1415498434453:dw|
|dw:1415498491744:dw|
Mark the x-coordinate. |dw:1415498681333:dw| Can you find the y-coordinate?
-1, -1?
Yes
how would I explain how I got the y? just say that I drew the line at -135 and looked at what y is when x is -1?
Have you learnt trigonometric ratios?
like sine, cosine, tangent, etc?
Yes
would tan(-135)=\(-\tfrac{y}{1}\) be correct?
\[\tan(-135) = \frac{y}{-1}\]
tan(-135)=1 1=y/-1 *-1 -1=y
y=-1 Make sure you have the unknown on the left of the equation.
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