Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

determinant of linear map link: http://puu.sh/cJBk2/581a41f86e.png

OpenStudy (anonymous):

@asnaseer @dumbcow

OpenStudy (anonymous):

is it just find a matrix that when the 1st matrix multiplies with that, it gives the 2nd matrix

OpenStudy (dumbcow):

yeah so \[f = \left[\begin{matrix}a &b \\ c & d\end{matrix}\right]^{-1} (..)\]

OpenStudy (dumbcow):

the 2nd part matrix is in parenthesis

OpenStudy (anonymous):

ok this is how i see it, let 1st matrix=A, 2nd matrix=B, the matrix we want to find=C AB=C B=A^-1*C det(B)=det(C)det(A)^-1

OpenStudy (anonymous):

am i right?

OpenStudy (dumbcow):

change B and C around we want to find matrix B

OpenStudy (anonymous):

why we want to multiply the A(the input matrix) with C(the output matrix)? :c

OpenStudy (anonymous):

WAIT MY BAD LOL I CHOKED WHEN I WROTE U ARE RIGHT

OpenStudy (anonymous):

a friend of mine suggested another solution, he said something like first choose a basis, then find the target in terms of basis, write that as f_basis, then find det() is he making any sense? :x

OpenStudy (dumbcow):

possibly it sounds good, sorry im not very good when it comes to change of basis

OpenStudy (dumbcow):

your equation will work though det(f) = det(C) * 1/det(A)

OpenStudy (anonymous):

kk man thanks a lot!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!