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vertical asymptote of y= (x^4-2x^3+x^2)/(3x^3-9x^2+6x)
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factor the numerator ad denominator cancel any common factors x^2(x^2 - 2x + 1)/3x(x^2 - 3x + 2) which then factors to \[\frac{x^2(x - 1)^2}{3x(x -1)(x-2)}\] any common factors will be points of discontinuity... after removing the common factors, what's left in the denominator will help you get the vertical asymptote. remember, vertical asymptotes are the values of x that make the denominator zero
so x =2
that's the only vertial asymptote, If you grah the curve using https://www.desmos.com/calculator you would see it
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