Question

If m =3 + 2p^2 and n=4 + p(sqrt2), what is m in terms of n?

A. 4n^2 + 16n + 32
B. 4n^2 + 16n(sqrt2) + 29
C. 4n^2 + 16n(sqrt2) + 35
D. n^2 - 8n +19
E. n^2 +8n +19

Can someone help me figure out how to set up for this problem? I don't know where to start.

Answer 1

you have to solve second equation for p

Answer 2

\[n = 4 + p \sqrt{2} \]
second equation this right ??

Answer 3

if your equation look like this
so subtract 4 both side and then divide sqrt 2

Answer 4

So \[n-4/\sqrt{2}=p\]?

Answer 5

yes now plug into the first equation where p is

Answer 6

m = 3 + 2(n-4/(sqrt2)^2

Answer 7

yes good so
so you can write that like this