Question

why can't a quadratic equation have one imaginry solution

Answer 1

It can

Answer 2

No it can't. ^

Answer 3

The quadratic formula contains a plus-minus sign, meaning there will always be pairs of answers.

Answer 4

One repeated solution

Answer 5

Hm...I didn't think of that @HelpAndNeedHelp! ....

Answer 6

Double roots do exist...but are they considered one solution, or two?

Answer 7

no it can't. one repeated solush is for real. sorry.

Answer 8

Oh, right....lol, ok.

Answer 9

Yeah, cause when you have an imaginary root in a quadratic equation, it's conjugate is also a root.

Answer 10

no repeated imaginary solution, be because for example.

(x + a)^2 = -b
and b is more than zero, (when b=0 we get repeated real solution)

x = +-i sqrt b - a

You see what I mean? It's just my bad :)

Answer 11

So...@halecha10 , do you understand?

Answer 12

YOU JUST CANT

Answer 13

@haleecha10

Answer 14

And @matlee please don't comment on questions when you can't add something helpful. Thank you.

Answer 15

@haleecha10 you need to cooperate -_-

Answer 16

Im just tryna make the conversation last, that is helpful

Answer 17

I think @haleecha10 left...maybe technical difficulties?
@matlee no point in extended a "conversation" when the asker has received an answer

Answer 18

extending...not extended

Answer 19

But the answer isnt solid

Answer 20

Um....yes it is. @matlee We had some discrepancies at first, but they are resolved and the correct answer has been put.

Answer 21

Lol Novembers fools. Havea good day

Answer 22

ok??

Answer 23

Quadratics, when graphed, are either shaped like a "U" or an upside down "U". When it doesn't cross the x-axis you have 2 imaginary answers.
How can an equation shaped like a "U" only cross the x-axis just once?

Answer 24

I just noticed Halleecha was offline

Answer 25

@wolf1728
https://www.desmos.com/calculator/cxk5pyumwy

Answer 26

StudyGirl14,
In the graph you just posted, it crosses the x axis in only one place, where 'x' = -1
If we factor x^2 + 2x +1 = 0 we get
(x+1) * (x+1) = 0
So, BOTH solutions are x=-1

Perhaps I should have explained it as "to have an imaginary answer AND a real answer you would need a graph that crosses the x-axis just once and doesn't cross the x-axis at all."
That contradictory statement shows why you have to have both answers real or both answers imaginary.

Answer 27

:)
I wish I could give you a medal @wolf1728 , but I already gave it to helpandneedhelp