PLEASE HELP ME
Okay, so here's the formula: \(\large 70(2\frac{45}{60})+15(\frac{40}{60})\tt =the~answer\) Just simplify
make sure to convert \(\large 2\frac{45}{60}\) into an improper fraction.
B?
@StudyGurl14
Nope, not B
im second answer is D then
That's incorrect as well.
Use distance = speed times time, d=st calculate distance for each situation and combine them for the trip, as instructed by StudyGurl14
Do you want me to show the steps @judtpleasegahd ?
sure but last answer C?
lol, yeah that's the answer. I'll show the steps...
ok
\(\large 70(\frac{165}{60})+15(\frac{2}{3})\rightarrow 70(\frac{11}{4})+\frac{30}{3}\rightarrow\frac{770}{4}+10\rightarrow 192\frac{1}{2}+10\rightarrow 202\frac{1}{2}\)
if i look like megan fox will you answer my questions <3
It was cut off... \(\large \rightarrow 202\frac{1}{2}\)
thank you that makes sense @StudyGurl14
You're welcome. I hope the answer is correct this time, lol. I'm 99.99% positive it is...lol
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