Question

For an object falling freely from rest (disregarding air resistance), the distance the object falls varies directly as the square of the time.

If an object is dropped from a 637 foot cliff and hits the ground in 7 seconds, how far did it fall in the first 3 seconds?

117 feet
273 feet
108 feet
137 feet

Answer 1

@StudyGurl14

Answer 2

137

Answer 3

"The distance the object falls varies directly as the square of the time"
Distance: d
time: t
k = constant
\(\large d=kt^2\)
First, solve for k by plugging in 7 for t, and 637 for d.
Next, find the answer by plugging the value you get for k back into the equation, and substitute 637 for d, and solve for t.

Answer 4

oops, sorry I mean for the next step, plug in 3 for t, and solve for d

Answer 5

Just do this first...lol:
\(\large (637)=k(7)^2\)
solve for k

Answer 6

4459

Answer 7

nad by the way, @matlee 's answer is incorrect

Answer 8

dont listen to her i have a 50% in algerbra 2

Answer 9

nope @judtpleasegahd
\(\large 637 = 49k\rightarrow k = \frac{637}{49}\tt =the~answer\)

Answer 10

by "the answer" I don't mean the answer of the entire problem. I just mean the value of k.

Answer 11

13

Answer 12

and @matlee ....? That's not a good grade...

Answer 13

correct

Answer 14

Now, substitute 3 for t, and 13 for k in this equation, and solve for d
\(\large d=kt^2\)

Answer 15

i think its pretty decent

Answer 16

ty, not to be rude or mean at all but what do you mean by 50% ? @matlee

Answer 17

50% is an F

Answer 18

Like failing

Answer 19

thats what i was thinking i just didnt want to be rude

Answer 20

In my mind, F is horrible, D is bad, C is ok, B is good, A is excellent

Answer 21

ty jud youve learened the lesson i wanted people to learn, ask before assuming :0 even if your asnwers could never be wrong just like math :p

Answer 22

@StudyGurl14 same

Answer 23

so...how is it "pretty decent" @matlee ???

Answer 24

let me stay focus lol @StudyGurl14 what were we saying

Answer 25

lol ok @judtpleasegahd

Answer 26

Lol goodluck to you guys goodluck onr your homewokrs

Answer 27

Let me type it again so you can see it clearly...@jud

Answer 28

ok

Answer 29

Now, substitute 3 for t, and 13 for k in this equation, and solve for d
\(\large d=kt^2\)

Answer 30

3*13

Answer 31

39?

Answer 32

not exactly...remember the exponent
So...
\(\large d=(13)(3)^2\)

Answer 33

And remember, \((3)^2=(3)(3)\)

Answer 34

177

Answer 35

If you meant 117, then yes

Answer 36

thank you :))

Answer 37

Anytime, my friend. \(\large\ddot\smile\)