Question

Find the angle \theta that maximizes the area of the isosceles triangle whose legs have length l=31.

Answer 1

I'm looking at the formula for area of any triangle as A = one-half the product of any two sides and the sine of the included angle.

A = (1/2) (41)(41) sin (theta)

To maximize area, what value of theta gives sin(theta) its maximum value. That's the answer.