Question

Which point lies on a circle that is centered at A(3, 3) and passes through B(6, 5)?

Answer 1

you know the center. so you know the

\(\Large\color{blue}{ \underline{(x-h)^2+(y-k)^2}=r }\)

To find the radius, find the distance between the 2 points.

Answer 2

what do i plug in for h and k?

Answer 3

(h,k) is the centre

Answer 4

(h,k) is the center of the circle.
And you are given that the center is (3,3)

Answer 5

ohh okay so i just plug it in then
its like 13?

Answer 6

\(\Large\color{blue}{ (x-\underline{h})^2+(y-\underline{k})^2=r }\)

\(\Large\color{blue}{ (x-\underline{3})^2+(y-\underline{3})^2=r }\)

Answer 7

Now, find the distance.
The distance between (x1,y1) and (x2,y2) is given by the formula,

\(\LARGE\color{black}{ distance=\sqrt{(y_1-y_2)^2+(x_1-x_2)^2} }\)

Answer 8

3.6?

Answer 9

\(\LARGE\color{black}{ distance=\sqrt{(y_1-y_2)^2+(x_1-x_2)^2} }\)

\(\LARGE\color{black}{ distance=\sqrt{(3-5)^2+(3-6)^2} }\)

\(\LARGE\color{black}{ distance=\sqrt{(-2)^2+(-3)^2} }\)

\(\LARGE\color{black}{ distance=\sqrt{4+9} }\)

\(\LARGE\color{black}{ distance=\sqrt{11} }\)

\(\LARGE\color{black}{ distance≈3.3166 }\)

Answer 10

about 3.32

Answer 11

4+9 isnt eleven though

Answer 12

And the distance between the 2 point is/was the radius.
So how would you write the equation of the circle ?