Medal to the first right answer!!with soln.. Integral of {x^2/(xsinx+cosx)}dx
\[\int\limits_{?}^{?}{x^2}/(xsinx+cosx)\]
question?
here you go!!
that is too hard...
\[\int\limits_{?}^{?}{{x^2}/(xsinx+cosx)}dx\]
believe me I know
spent the whole day!!
@Preetha
@ParthKohli @dan815 @SolomonZelman
@Whitemonsterbunny17 @robtobey @.Sam.
@Compassionate
cmon guys @least give it a try!!
i got it :)
@SolomonZelman
wow..........how??
Either ur a genius OR ur wrong...
Shoot!!
i post it ok
pls do
uhhh im in advanced math and I have never done this...sorry
eait what grade you in
eat my grade??........did you solve it??
I am guessing no!!
dude or girl i need to known what grade your in or i cant help you
@kag @Owlfred @LiteNing1337 @Abhisar @skullpatrol @Secret-Ninja @Compassionate @demonchild99 @ganeshie8 @emmigrace222 @mathstudent55
what makes you think there exists a closed form for this ?
dont getcha!!
Is it solvable......I didnt check wolfram!!
cuz I solved a different but similar one!!
im not so sure if il able to work an integral that wolfram gave up :O http://www.wolframalpha.com/input/?i=Integral+of+x%5E2%2F%28xsinx%2Bcosx%29+dx
\[\int\limits_{?}^{?}{ x^2/{(xsinx+cosx)^2}}\]
lol dude......anyways just wanted to make sure no one else can solve this!!
@Princer_Jones @perl
one sec
one sec
BTW The second one I posted is xtremely tricky....anyone wants the sol??
integral x^2 / ( xsin x + cosx) is not an elementary antiderivative
\[{xsecx.xcosx/{(xsinx+cosx)^2}}\]
you want the indefinite integral or the definite integral, i notice you have question marks in your limits
u have to do like this for the original question
indefinite
this was the original question Integral of {x^2/(xsinx+cosx)}dx ?
ok you did sec x * cos x = 1 , i follow so far
yes...........the one I posted some comments bfore is another form of it which I solved
why is there suddenly a square term in the denominator?
in your original question there was no square term in the denominator
scroll up to your original integral
\[next xsex=f(x)(1st function) and (xsinx+cosx)=g(x)(2nd function) and then use ILATE\]
stop. look at your original integral above, there is no square term
yes thats the reason I am not able to solve it
I solved a different version of the same question...
without the square term, it is unsolvable. with the square term, it is solvable
k......closing the question .......m out!..................THANKS guys!!................Peace..\/
thats what I figured!!
you spent a whole day on an unsolvable integral. here is one integral sqrt(sinx) , good luck
I know this already
already wasted my time on this
the power if in the denominator is 2, then it is easily solvable... And it is not compulsory for every function to have a closed integral .. As easy an integral like integral of sin x/x dx is not possible to have a closed form. @cambrige
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