@KamiBug
What is the solution to the equation? 3- z/4 = 8 A. z = –44 B. z = –20 C. z = 20 D. z = 44
I NEED HELP PLEASE I AM BEGGING
First subtract 3 from both sides. -z/4 = 5 Multiply both sides by 4. -z = 20 Make z positive. z = -20.
I ahevanother please
What is the solution to the equation? 2q + 18 = –5q – 3 A. q = –5 B. q = –3 C. q = 3 D. q = 5
@KamiBug please why do you keep leaving
B. q = -3
i haev another please
What is the solution to the equation 2(m-8) = 4(m+6)
\[2\left( m-8 \right)=4\left( m+6 \right)\]
Distribute the factor into what's in parenthesis by multiplying it by each term. Do this for both sides. 2m - 16 = 4m + 24 Add 16 to both sides. 2m = 4m + 40 Subtract 4m from both sides. -2m = 40 Divide both sides by -2. m = -20
The product of 3 and a number is 12 more than the sum of the number and 26. What is the number?
Here is the equation you want to use: 3x = x+26+12 First add like terms on the right side. 3x = x+38 Subtract x from both sides. 2x = 38 Divide both sides by 2. x=19
yay i got an 100% do you mind helping me with more yes or no:)
I don't mind. :)
ok one second i nee dhelp with english is that ok
I'll do my best:) Though I'm more of a math person. :P I suggest you post it in the English section in case I can't answer. :3
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