Suppose the population of a town is 3,400 in 2000. The population decreases at a rate of 2% every 20 years. What will be the projected population in 2040? Round your answer to the nearest whole number.
Probably you know that an exponential function is written in this form: \(\large{f(x) = ar^x}\) Where a is the initial value (in this case 3,400) and r is the rate. If the rate were applied every year and you were told to find the value/quantity after the 1st year, you'll set x=1 (the exponent will be 1), right? If it were for the 2nd year, you'll set x = 2 (the exponent will be 2) and so on. In this problem, the key is in how to make the exponent 1 when x = 20; 2 when x= 40 and so on (because the rate is applied every 20 years). Well, you can do so, by setting a fraction in the exponent: \(\large{f(x) = ar^{\frac{x}{t}}}\), where t is the time by which the rate applies ''completely'', so to speak. In the problem it would be in this way: \(\large{f(x) = ar^{\frac{x}{20}}}\) And your r should be the portion of the population that were left after x year.
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