A car traveling at 46 mph decelerates at 29 feet per second per second.

How long does it take for the car to come to a complete stop?
ANSWER: It takes seconds.

What distance is required to bring the car to a complete stop?
ANSWER: feet.

Question

A car traveling at 46 mph decelerates at 29 feet per second per second.

How long does it take for the car to come to a complete stop?
ANSWER: It takes seconds.

What distance is required to bring the car to a complete stop?
ANSWER: feet.

anonymous · Answer

What kinematic equations do you have?

anonymous · Answer

That is it.  It is an anti derivative equation.  Integrals

anonymous · Answer

Well I'm only used to the metric system and I don't feel like converting so I can just help you out with the equation and what not. So it will require a kinetmatic equation as I mentioned above think about which one you could use.

$$v_0 = 46 ~~~~v=0~~~a = -29 $$ you can put in units and stuff but think about it and see what you get. 

I'll bbl.