HELP
The following formula models the number of prison inmates, P, in thousands, who are in U.S. prisons x years after 1980. P = 2 x^2+24 x+318 Find the first year in which the population of U.S. prisons was approximately 638 thousand people. Answer: The population reached 638 thousand people in the year
@jim_thompson5910
\[P(x)=2x ^{2}+24x+318\]
Correct?
Wait now, You are looking for how much population?
no the year when the population was 638
i ment 638 thousand
So you know how a function works? X is the value you input (in this case years) and P(x)=population at x-years. Yes?
P is already in thousands so if P = 2 for instance, then you have a population of 2,000 (not just 2)
\[638=2x^2+24x+302\]
Mertsj has the right equation because P = 638 means the population is 638,000
@Mertsj, thats correct.
so x=-20 and x=8
wait chck this before you stated this was the first equation P(x)=2x2+24x+318 but you said you wrote it like this 638=2x^2+24x+302 is it 318 or 302
+318
matlee has a good point that I didn't notice
thnx jim ok so would the answer still be right?
which answer are you referring to?
x=-20 x=8
Sorry guys keep losing connections is that happening to anyone else
then you ignore the negative answers because x is the number of years after 1980
ok nevermind it went through
yeah the site is weird sometimes
so the only answer is x = 8
but it says in what year is 8 a year?
so whats the final answer?
x = 8 is the number of years after 1980 so you simply add 8 to 1980 to get 1988
your a genious
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