Will medal Solve. -1/4y = 16
-64
idk
First multiply -1 on both sides of the equation since you are dividing -1 in the orignal problem \(\Large \frac{-1}{4y}~=~16\) \(\Large -1 \times \frac{-1}{4y}~=~16\times -1\) \(\Large 4y~=~16\times -1\) So what is 16 x -1?
-16
Um...@sammixboo you made a mistake
\(\large -1\times\frac{-1}{4y}\neq 4y\)
dang again sammi tisk tisk tisk
Just do this: \(\large -\frac{1}{4}y=16\rightarrow -4(-\frac{1}{4}y)=16(-4)\rightarrow y = -64\)
Thanks :)
Good now we plug in -16 where 16 x -1 was \(\Large 4y~=~-16\) Now we must multiply 4 on both sides og the equation since we are dividing \(\Large 4y \times 4~=~-16\times4\) \(\Large y=~-64\)
Oh i see what you did there i didnt know you could do it like that
Strangely enough, although you made several mistakes @sammixboo , you still "got" the right answer.
You can't @matlee . Not really.
I just skipped steps It cancels each other out and all
No she multiplied by 1 in the first place
It's how I learned it
then she did the 4 after
although it was suppose to be 1/4 first then the 4
I am not sure how it works, but it always turn out as the right answer. I never really got it
It defies the rules of algebra....
I think you made some mistakes, but you fixed it in your head, without showing every single step on here, so it came out okay. :) Weird, but if it works for you, then whatever. xD @sammixboo
But I know your way is a right way I just never learned it like that
Well Study no offense but at the end she was right and it seem to me like common sense so....
Im out to the next question
:) I never been good at explaining math DX But my teacher just showed me another way to explain somewhat how I got my answers and that is how I have been doing it since I was 11
@Here_to_Help15 It's not common sense. Because... \(\large 4x\times 4=-16\times4\rightarrow16x=-64\)
I think it is just some kind of cheat to skip some steps, but still get the same answer
(replace the x's with y's sorry)
I know. It is that the 4x cancels out the times 4
Like I said, if you get the right answer, then by all means do it. :) Just cause I don't understand the process doesn't mean that it's a wrong process. Maybe one day you can teach me your method @sammixboo \(\large\ddot\smile\)
My teacher explained a loooong explanation about how it works when I was younger, but I never really payed attention to that explanation, but it has always gotten me the right answer :)
Dont worry guys ill call my math teacher
:)
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