Question

Simplify. Write your answers without exponents. (1/32)^-2/5

Answer 1

\[(1/32)^{-2/5}=\sqrt[5]{32^2}=\sqrt[5]{(2*2*2*2*2)^2}=\sqrt[5]{2^{10}}=\]

Answer 2

Should be =4

Answer 3

the fifth root of 32 is 2 because \(2^5=32\)
then \(2^2=4\)

Answer 4

\[\Large \sqrt[5]{2^{10}} = 2^{10/5} = 2^2 = 4\]

so there are at least 2 ways to do it