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OpenStudy (anonymous):
10 % of students in a college class are left handed. A statistics instructor, looking at the class roll, observed that there are 15 students in his class. on the first day of class, what is the probability that he will find between 3 and 7 left handed students? Both numbers are included Binomial distribution section 5.3
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OpenStudy (anonymous):
this is going to be a drag
OpenStudy (anonymous):
i know n=15 and p=.1 but x (number of successes) i dont know what to put
OpenStudy (anonymous):
\[P(x=3)=\binom{15}{3}.1^3\times 0.9^{12}\] just for the first one
OpenStudy (anonymous):
\[P(x=4)=\binom{15}{4}.1^4\times 0.9^{11}\]
OpenStudy (anonymous):
then \(P(x=5)\) and \(P(x=6)\) and \(P(x=7)\) and then add them up your math teacher must hate you
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