Question

need help

k^3-k + (k+2)!/(k-1)! = (k+1)^3-k+1

Answer 1

\[k^3-k+\frac{(k+2)!}{(k-1)!}\]??

Answer 2

or is is all in the numerator?

Answer 3

is a problem of mathematical induction

Answer 4

yeah i figured that i was just trying to ascertain if i wrote it correctly

Answer 5

yes u wrote it correctly

Answer 6

ok then do you know how to reduce
\[\frac{(k+2)!}{(k-1)!}\]

Answer 7

thats my problem

Answer 8

i forgot how this so looks familiar thou

Answer 9

if you wrote out the first few terms it will be completely obvious

Answer 10

ok ill write it out

Answer 11

\[(k+2)!=(k+2)(k+1)k(k-1)(k-2)...\]

Answer 12

is it clear that everything cancels except the first three terms?

Answer 13

yes we use the bottom as the end

Answer 14

so only the end cancels out

Answer 15

so then i can make them equal by rearranging them right