Question

Please help and im lost on these type of problems

Determine the best method to solve the system of equations. Then solve the system.
1/4x+3/4y=1
2x+6y=8

A.substitution
B. Elimination using multiplication; no solution
C. Elimination using subtraction
D. Elimination using multiplication; infinitely many solutions

Answer 1

Any ideas at all?

Answer 2

im thinking c

Answer 3

nope not really :(

Answer 4

Nice try but no.

Answer 5

By just looking at the problem, you can get rid of A and C.

Because with substitution, it would be nice to have a variable with no coefficient in either one of the equations, which you don't have.

And subtraction would be ugly because you'll be subtracting fractions.

So now you're left with B or D with is elimination by multiplication

Answer 6

might i make a suggestion??
\[1/4x+3/4y=1\\ 2x+6y=8 \] multiply the first equation by \(8\) and see what you get

Answer 7

Is the first equation

1/4x + 3/4y=1
Or
(1/4)x + (3/4) y = 1

Answer 8

1/4x+3/4y=1x8
right

Answer 9

No.
What's (1/4x) (8)?
And (3/4x) (8)?

Answer 10

its 1/4x+3/4y=1

Answer 11

i got 6x @nikato

Answer 12

Oops. Typo.

If you multiply both sides by 8, you get have

8(1/4x + 3/4y) = 1(8)
So
(1/4x) 8 + (3/4y) 8 = 8
Can you simplify the left side?

Answer 13

i think so

Answer 14

im starting to guess its B. or D.

Answer 15

im guessing D.... am i right @nikato

Answer 16

That is absolutely correct.!

Answer 17

Because if you were to simplify that^,
You would get 2x+6y=8
Which is exactly the same as the second equation.
Since they are the SAME equation, they would share/have all the same answers