Question

f(x)=-2x^3-x^2+4x+4
Find the average slope of this function on the interval(1,2)=
By the mean value theorem, we know there exists a c in the open interval(1,2) such that f'(c) is equal to this mean slope. Find the value of c in the interval which works..

Answer 1

you need two numbers first
\[f(2)\] and
\[f(1)\] did you find them?

Answer 2

yes

Answer 3

what are they?

Answer 4

-8 and 5

Answer 5

ok then
\[\frac{f(2)-f(1)}{2-1}=\frac{-8-5}{1}=-13\]

Answer 6

next you need the derivative
what is that?

Answer 7

-6x^2-2x+4

Answer 8

ok final job is to solve
\[-6x^2-2x+4=-8\] and you are done

Answer 9

oh ok thank you

Answer 10

yw

Answer 11

wyhooo mistakE!!

Answer 12

\[-6x^2-2x+4=-13\] is more like it

Answer 13

About to say xD

Answer 14

hmm ok

Answer 15

yeah must be my bedtime