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Mathematics 16 Online
OpenStudy (anonymous):

can someone help me with geometry questions? ill give you a medal + fan. please?

OpenStudy (anonymous):

Question?

OpenStudy (anonymous):

ill attach a picture give me a second

OpenStudy (anonymous):

OpenStudy (anonymous):

AC = 30 , m<ECB =27degrees

OpenStudy (anonymous):

This is because in a rectangle, diagonals bisect each other and they're congruent

OpenStudy (anonymous):

thank you can you help me with some more?

OpenStudy (anonymous):

Sure haha

OpenStudy (anonymous):

since this is an assessment, you should honestly do it yourself, but nevertheless here's an explanation: Since we know that ABCD is a rectangle, we actually know a few things: 1) AC = BD 2) AE = BE = DC = CE 3) <EAB = <ABE = <EDC = <ECD 4) AD = BC 5) AB = DC 6) All the angles of the rectangle itself are 90 degrees To solve for AC: since we know that AE = BE we can actually solve for x and get the actual side length: \[AE = BE\] \[3x+6 = 6x -3\] (I will leave it to you to solve this, unless you don't know how to do so, then I will help you do so) Now once we the value of x and plug it in to get the length of AE. We know that EC = AE, thusly we know that AC = 2AE. To solve for m<ECB: so we know that <ECB = <EBC, because EB = CE and thus EBC is an isosceles triangle. Thus if we solve for m<EBC we will get m<ECB. Now <EBA and <EBC make up a 90 degree angle. And so we know that \[<EBA +<EBC = 90\] since we know the value of EBA we can plug that in so\[63+<EBC = 90\]and solve for <EBC, which we know is the same value as m<ECB

OpenStudy (anonymous):

I am absolutely horrible at everything in math

OpenStudy (anonymous):

I believe it is (4,6)

OpenStudy (anonymous):

how did you find that?

OpenStudy (anonymous):

http://www.algebra.com/algebra/homework/Parallelograms.faq.question.746030.html This isn't the same question, but this is an example of a different problem on how to solve for the fourth vertex. Take a look at it and see if you understand it.

OpenStudy (anonymous):

oh okay i get it. thank you so much.

OpenStudy (anonymous):

You're welcome.

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