can someone help me with geometry questions? ill give you a medal + fan. please?
Question?
ill attach a picture give me a second
AC = 30 , m<ECB =27degrees
This is because in a rectangle, diagonals bisect each other and they're congruent
thank you can you help me with some more?
Sure haha
since this is an assessment, you should honestly do it yourself, but nevertheless here's an explanation: Since we know that ABCD is a rectangle, we actually know a few things: 1) AC = BD 2) AE = BE = DC = CE 3) <EAB = <ABE = <EDC = <ECD 4) AD = BC 5) AB = DC 6) All the angles of the rectangle itself are 90 degrees To solve for AC: since we know that AE = BE we can actually solve for x and get the actual side length: \[AE = BE\] \[3x+6 = 6x -3\] (I will leave it to you to solve this, unless you don't know how to do so, then I will help you do so) Now once we the value of x and plug it in to get the length of AE. We know that EC = AE, thusly we know that AC = 2AE. To solve for m<ECB: so we know that <ECB = <EBC, because EB = CE and thus EBC is an isosceles triangle. Thus if we solve for m<EBC we will get m<ECB. Now <EBA and <EBC make up a 90 degree angle. And so we know that \[<EBA +<EBC = 90\] since we know the value of EBA we can plug that in so\[63+<EBC = 90\]and solve for <EBC, which we know is the same value as m<ECB
I am absolutely horrible at everything in math
I believe it is (4,6)
how did you find that?
http://www.algebra.com/algebra/homework/Parallelograms.faq.question.746030.html This isn't the same question, but this is an example of a different problem on how to solve for the fourth vertex. Take a look at it and see if you understand it.
oh okay i get it. thank you so much.
You're welcome.
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