Question

how do you differentiate 3sin^2(x)cos(x)

Answer 1

use product and chain rules

Answer 2

would it be 6sinxcosx-3sinx?

Answer 3

Seems unlikely. Who told you that? Please show YOUR work.

Think a little harder about the Chain Rule.

Answer 4

d/dx[f(g(x))*h(x)] = f'(g(x))*g'(x)*h(x)+h'(x)*f(g(x))

Answer 5

If you don't want to use product rule, you may consider simplify the expression a bit.
\[3\sin^2(x)\cos(x) = \frac{2\times\sin(x)\times \cos(x)\times 3\cos(x)}{2}=\frac{3\sin(2x)\sin(x)}{2}\]
Then use \(\sin(a)\sin(b) = \frac{1}{2}(\cos(a-b)-\cos(a+b))\) to further simplify it. It should be pretty easy to integrate.

Answer 6

Lets start with this :
What is the derivative o 3sin^2(x)

Answer 7

i got it thanks 6sinxcos^2x-3sin^3x

Answer 8

gotta go to school now!

Answer 9

thats correct