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Mathematics 9 Online
OpenStudy (anonymous):

Which of the following could be points on the unit circle?

OpenStudy (anonymous):

OpenStudy (sidsiddhartha):

equation of a unit circle with coordinates (x,y) is \[x^2+y^2=1\] now check for which pair above equation is satisfied

OpenStudy (anonymous):

n

OpenStudy (sidsiddhartha):

??

OpenStudy (anonymous):

1,1?

OpenStudy (sidsiddhartha):

ok try the second option \[x=-2/3\\y=\sqrt{5}/3\]

OpenStudy (sidsiddhartha):

square them and add them up and see if u get 1

OpenStudy (sidsiddhartha):

any luck?

OpenStudy (anonymous):

yes I got 1

OpenStudy (sidsiddhartha):

\[x^2+y^2=[\frac{ -2 }{ 3 }]^2+[\frac{ \sqrt{5} }{ 3 }]^2=4/9+5/9=9/9=1\]

OpenStudy (sidsiddhartha):

yes thats why this is on unit circle, try the other option you will not get 1.

OpenStudy (anonymous):

ohhhhhhh so it's 1,1 and -2/3, 5/3?

OpenStudy (sidsiddhartha):

no 1,1 is not correct because \[1^2+1^2 \neq1~~so~this~is~eliminated\\ [\frac{ \sqrt{3} }{ 2 }]^2+(1/3)^2 \neq 1,this~is~eliminated\\ (0.8)^2+(-0.6)^2=1,so~this~is ~correct\\ (-2/3)^2+(\sqrt{5}/3)^2=1,so ~this~is~also~correct\]

OpenStudy (sidsiddhartha):

so u have to take the numbers then square them add add them. if the addition produces 1 then they will be on unit circle,if not 1 then they will be not :)

OpenStudy (anonymous):

ohhh ok I see

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