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OpenStudy (fanduekisses):

Calculus Rate of Change help

OpenStudy (fanduekisses):

The length L of a rectangle is decreasing at the rate of 2cm/sec while the width W is increasing at the rate of 2cm/sec. when l=12 cm and w=5cm, find the rates of change of a) the area, b) the perimeter, c) the length of a diagonal of the rectangle

OpenStudy (fanduekisses):

I already did a and I got da/dt= -14 cm^2/sec

OpenStudy (cj49):

perimeter=2l+2w 24+10=34 dl=-2 dw=5 2dl+2dw=2(-2)+2(2) -4+4cm/sec

OpenStudy (fanduekisses):

ohh so the perimeter doesn't change

OpenStudy (fanduekisses):

Now for part c, do I use the Pythagorean Theorem?

OpenStudy (cj49):

yes

OpenStudy (fanduekisses):

Ok so I have dc/dt=1/2(L^2+W^2)*2L*dL/dt + 2W*dW/dt

OpenStudy (cj49):

Find the rate of change of the diagonals. Let D = a diagonal of the w by L rectangle, By Pythagorean theorem, D^2 = w^2 +L^2 So, D = sqrt[w^2 +L^2] Or, D = [w^2 +L^2]^(1/2)

OpenStudy (fanduekisses):

ok after taking the deriv i get dc/dt=1/2(L^2+W^2)*2L*dL/dt + 2W*dW/dt

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