Calculus Rate of Change help
The length L of a rectangle is decreasing at the rate of 2cm/sec while the width W is increasing at the rate of 2cm/sec. when l=12 cm and w=5cm, find the rates of change of a) the area, b) the perimeter, c) the length of a diagonal of the rectangle
I already did a and I got da/dt= -14 cm^2/sec
perimeter=2l+2w 24+10=34 dl=-2 dw=5 2dl+2dw=2(-2)+2(2) -4+4cm/sec
ohh so the perimeter doesn't change
Now for part c, do I use the Pythagorean Theorem?
yes
Ok so I have dc/dt=1/2(L^2+W^2)*2L*dL/dt + 2W*dW/dt
Find the rate of change of the diagonals. Let D = a diagonal of the w by L rectangle, By Pythagorean theorem, D^2 = w^2 +L^2 So, D = sqrt[w^2 +L^2] Or, D = [w^2 +L^2]^(1/2)
ok after taking the deriv i get dc/dt=1/2(L^2+W^2)*2L*dL/dt + 2W*dW/dt
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