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Mathematics 14 Online
OpenStudy (anonymous):

Hello all, I'm kinda new and need some math help...

OpenStudy (anonymous):

a

OpenStudy (studygurl14):

@INEEDSOMUCHHELP \(\Large\sf\color{blue}{Welcome~To~OpenStudy!}\)

OpenStudy (anonymous):

Thankyou SOOOO Much!

OpenStudy (anonymous):

ty soo much

OpenStudy (anonymous):

If someone can get someone who can help assist me or give me directions in solving these problems, that would be greatly appreciated!

OpenStudy (studygurl14):

You're welcome. However, I stink at statistics, since I have never taken it. I'm sorry. You can link to people's names to try to get them to help. For example @ganeshie8

OpenStudy (anonymous):

@thomaster @iheartfood @ParthKohli @Preetha @AriPotta @ganeshie8 @HelpBlahBlahBlah @johnweldon1993 @Lyrae @Zarkon @xEminemx14 @Compassionate @VortexAlliby @blurbendy @BTaylor @natsent06 @micahm

OpenStudy (natsent06):

yes?

OpenStudy (anonymous):

OpenStudy (natsent06):

uhhh hold that thought

OpenStudy (johnweldon1993):

Oh stats huh? wow this takes me back about 4 years lol hmm, well the first thing we need for question 1 would be the z-scores Do you know how to find those?

OpenStudy (johnweldon1993):

Hint...the formula is \[\large z = \frac{X - \mu}{\sigma}\] so we need the z-score for both 435 and 565

OpenStudy (anonymous):

yah, do u want for me to upload a sheet?

OpenStudy (anonymous):

oh ok one sec

OpenStudy (johnweldon1993):

No that wont be necessary :)

OpenStudy (anonymous):

ok? so what do I do?

OpenStudy (johnweldon1993):

So for the z-score for 435 we take X to be 435...the mean \(\large \mu\) will be 500 and the standard deviation \(\large \sigma\) will be 65 so if we plug that into that formula up there...what do we get for 'z'?

OpenStudy (anonymous):

ok one sec

OpenStudy (anonymous):

-1

OpenStudy (johnweldon1993):

Correct...so keep that to the side for a moment while we do the same thing for the z-score of the 565 that we have again, same formula except this time X = 565

OpenStudy (anonymous):

ok one sec

OpenStudy (anonymous):

1

OpenStudy (johnweldon1993):

Indeed...okay...we have our 2 z-scores...that's all we need to begin to figure this out What we need to do...is take those 2 values for 'z' and look at a z-score table and find the corresponding value We want the probability that Z < 1 and the probability that Z < -1 So look on your table (I'm assuming you have one...I certainly do not lol) and look for Z = 1..and tell me what decimal is written in the column :)

OpenStudy (anonymous):

haha give me one second

OpenStudy (johnweldon1993):

Of course :)

OpenStudy (anonymous):

ty for being patient and helping me one more sec lol

OpenStudy (anonymous):

can u find one cuz i cant?

OpenStudy (johnweldon1993):

Ah got one... http://www.utdallas.edu/dept/abp/zscoretable.pdf so do me a favor and look at that page :)

OpenStudy (anonymous):

for -1 it converts to 0.1379 and for 1 it converts to 0.8643

OpenStudy (johnweldon1993):

Ahh now be careful....what you have chosen are in 2 different rows! if you look carefully at the toop of the graph...you'll see 0.00...0.01 etc...you chose one from the 0.00 row...but then you chose the other from the 0.09 row gotta be careful there... to look at the 0.0 row for each instance...and then tell me what the z-score is :)

OpenStudy (anonymous):

oh ok one sec

OpenStudy (anonymous):

1 is .8413

OpenStudy (anonymous):

@johnweldon1993

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