Question

GIVING MEDALS AND FANS!REALLY NEED HELPPP,PLZ!!!!

Given that P = (-9, 2) and Q = (-10, 9), find the component form and magnitude of 2(vector PQ)

Answer 1

the vector PQ , starting from point Q and ending at P is
found by subtracting
Q - P

Answer 2

A)<-2.-14>,SQUARE ROOT OF 100
B)<2,-14>,SQUARE ROOT OF 50
C)<-2,14>,SQUARE ROOT OF 200
D)<-38,14>,SQUARE ROOT OF 410

Answer 3

I calculated the component form which turned out to be <-1,7>

Answer 4

then i multiplied it by 2 to get <-2,14>

Answer 5

did i do it correct?

Answer 6

Q - P = <-10,9 > - < -9,2>

Answer 7

ok,then how do i find the magnitude?

Answer 8

@StarJ9 can u help me???

Answer 9

@perl ??

Answer 10

@Ash90

Answer 11

I don't see how it's q-p. Is P = (-9, 2) in component form? and if so wouldn't it be
P =(-9i + 2j)?

Answer 12

that's what i dont' get.i know that the component form part is right ,but i don't get the magnitude part.

Answer 13

because when you have a vector start at P and end at Q , to find the vector at the origin you solve Q - P