An object is launched horizontally from a table top at a speed of 18 m/s. It takes 0.6 seconds to hit the ground. What is the resultant velocity of the object at the time of impact

Question

An object is launched horizontally from a table top at a speed of 18 m/s.  It takes 0.6 seconds to hit the ground.  What is the resultant velocity of the object at the time of impact

michele_laino · Answer

Please, first you have to find the modulus of the vertical velocity, using the Torricelli formula

michele_laino · Answer

how is the relationship between the height of the table and the falling time?

anonymous · Answer

Our horizontal velocity will remain constant at 18 m/s
Our vertical velocity can be calculated by $$v=v _{0}+a*t$$ where v0 is zero
Plugging in -9.81 for a and .6 for t
vertical velocity $$v=-5.886 m/s$$
Final velocity is $$\sqrt{18^2+(-5.886)^2} = 18.938$$

michele_laino · Answer

Right!