Question

An object is launched horizontally from a table top at a speed of 18 m/s. It takes 0.6 seconds to hit the ground. What is the resultant velocity of the object at the time of impact

Answer 1

Please, first you have to find the modulus of the vertical velocity, using the Torricelli formula

Answer 2

how is the relationship between the height of the table and the falling time?

Answer 3

Our horizontal velocity will remain constant at 18 m/s
Our vertical velocity can be calculated by \[v=v _{0}+a*t\] where v0 is zero
Plugging in -9.81 for a and .6 for t
vertical velocity \[v=-5.886 m/s\]
Final velocity is \[\sqrt{18^2+(-5.886)^2} = 18.938\]

Answer 4

Right!