A 65.0 gram sample of some unknown metal at 100.0° C is added to 177.1 grams of water at 24.5° C. The temperature of the water rises to 27.0° C. If the specific heat capacity of liquid water is 4.18 J/ (°C × g), what is the specific heat of the metal?

0.285 J/ (°C × g).
0.390 J/ (°C × g).
1.05 J/ (°C × g).
2.56 J/ (°C × g).

Question

A 65.0 gram sample of some unknown metal at 100.0° C is added to 177.1 grams of water at 24.5° C. The temperature of the water rises to 27.0° C. If the specific heat capacity of liquid water is 4.18 J/ (°C × g), what is the specific heat of the metal?

 0.285 J/ (°C × g).
 0.390 J/ (°C × g).
 1.05 J/ (°C × g).
 2.56 J/ (°C × g).

anonymous · Answer

@Ash90

anonymous · Answer

ist here more info for this? ori s this it.

anonymous · Answer

No thats it :/ @Ash90

anonymous · Answer

okay i think  this is l ike this
20.0*0.500*1/1/35.0=0.286j/c*g so about 0.285c*G