Question

ALGEBRA 1 HELP EASYYYY please help and explain
3. The length of a rectangle is 7 mm longer than its width. Its perimeter is more than 62 mm. Let w equal the width of the rectangle.
a. Write an expression for the length in terms of the width.
b. Use these expressions to write an inequality based on the given information.
c. Solve the inequality, clearly indicating the width of the rectangle.

Answer 1

From your data we can write:
\[l=7+w\]
where l is length, and w is width

Answer 2

ok so that would be the expression?

Answer 3

please, try to express the perimeter in function of l and w

Answer 4

How would I do b?

Answer 5

\[2p=2*\left( l+w \right)\]
where 2p is the perimeter

Answer 6

ok but where would the 62 come into play?

Answer 7

from the text of your problem, we can write:
\[2p >62\]
now, please, try to substitute the formula above for 2p

Answer 8

Im so confused! Can anyone else help!!

Answer 9

\[2\times \left( l+w \right)>62\]

Answer 10

@StarJ9 can you help?

Answer 11

@perl

Answer 12

I don't see how anyone else would explain this better then what Michele posted.
Remember that the perimeter of a rectangle is p= w+w + l+l, or p = 2w + 2l, there are two widths, and two lengths. So, from above 2(w+l) he just factor the two out.

The perimeter is more then 62, so p > 62. We know what the perimeter is 2w+2l.
So, 2w + 2l > 62.

The length of a rectangle is 7 mm longer than its width. So, the length is the width + 7 more.

length = 7 + w

Putting it all together is 2w + 2(7+w) > 62

Answer 13

Solving for w gives us 12, and plugging w into l = 7 + (12) = 19.
w = 12
l = 19
2(12) + 2(19) = 62

...something is wrong...62 is not > 62...