Question

Write an equation in Slope-intercept form for the line that is parallel to the line y = -5/2 x + 6 and that passes through the given point (-4,-6). Show your work.

Please help!!!

Answer 1

you are given this equation

\[\Large y = -\frac{5}{2}x + 6\]

what is the slope of this given line?

Answer 2

-5/2 @jim_thompson5910

Answer 3

we need the equation of some line parallel to this one

Answer 4

all parallel lines have the same slope

so we know \[\Large m = -\frac{5}{2}\] for this new line

Answer 5

we are told that this parallel line "passes through the given point (-4,-6)"

all points are of the form (x,y) so

(x,y) = (-4,-6)

which means

x = -4
y = -6

Answer 6

now that we have the values of m, x and y, we can plug them into y = mx+b and solve for b

Answer 7

\[\Large y = mx+b\]

\[\Large y = -\frac{5}{2}x+b\]

\[\Large -6 = -\frac{5}{2}(-4)+b\]

solve for b

Answer 8

which would be

Answer 9

you tell me. It might be helpful to compute -5/2 times -4 to get

\[\Large -\frac{5}{2}(-4) = \frac{-5}{2}*\frac{-4}{1}\]

\[\Large -\frac{5}{2}(-4) = \frac{-5*(-4)}{2*1}\]

\[\Large -\frac{5}{2}(-4) = \frac{20}{2}\]

\[\Large -\frac{5}{2}(-4) = 10\]

Answer 10

so,

\[\Large -6 = -\frac{5}{2}(-4)+b\]

turns into

\[\Large -6 = 10+b\]

Answer 11

so b = ??