A linear function goes through the points (4,-3) and (9,7). find point-slope form, slope-intercept form, and standard form
So first the point slop form. (y-y1)=m(x-x1) You need to find the slope of the two points. \[\frac{ -3-7 }{ 4-9}= 2\]
Then plug in the information into the points. Point-slope, as the name suggests, rquires just a slope and one point. Because we found the slope, we can just pick one point and plug that in. (y+3)=2(x-4)
For slope-intercept (y=mx+b) you just need to expand the point-slope form. (y+3)=2(x-4) -> y= 2x-8-3 -> y=2x-11
Standard form is when all the variables are on the left side of the equation and the constant is on the right. Just use the point-slope and manipulate the equation (y+3)=2(x-4) -> y+3-2x=-8 -> -2x + y =-11
so what is the point slope form im confused on the answer
@ArkGoLucky
The point slope for is the first answer I gave
*form
After the slope
(y+3)=2(x-4) A line can defined by a point and slope so this equation gives the slope, in this case 2, and a point, in this case (4,-3)
Join our real-time social learning platform and learn together with your friends!