Question

A minimum energy of 242 kJ/mol is required to break the chlorine–chlorine bond in Cl2. what type of radiation is this

Answer 1

242 kJ/mol (which is the energy necessary to break one mole of Cl-Cl bonds)

so find the energy of a single bond, this is energy of one photon; use planck's equation

\(E_{photon}=h*\dfrac{c}{\lambda}\)

h= plancks constant = \(6.626*10^{-34}~J*s\)
c= the speed of light (in vacuum) =\(3.0*10^8~m/s\)
\(\lambda\) =wavelength

find the wavelength of the one photon

Look up the type of electromagnetic radiation it is