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Mathematics 19 Online
OpenStudy (anonymous):

Math help, please?

OpenStudy (anonymous):

What is the discontinuity of the function f(x) = the quantity of x squared minus 4 x minus 12, all over x plus 2

OpenStudy (anonymous):

@Nnesha Do you think you could help me out, please?

OpenStudy (nikato):

I think you just have to look at your denominator. Which is x+2 The discontinuity is when the denominator equals 0 So what value of x makes the denominator zero?

OpenStudy (anonymous):

2?

OpenStudy (nikato):

No. 2+2 doesn't equal 0

OpenStudy (anonymous):

-2

OpenStudy (anonymous):

Sorry, I missed that negative sign. Aha

OpenStudy (nikato):

Yes. So the discontinuity is x=-2

OpenStudy (anonymous):

well my answer choices are -6, 0 6, 0 -2, -8 2, -4 @nikato

OpenStudy (nikato):

Wel.. There's only one choice with -2

OpenStudy (anonymous):

Ok, thanks! I was going to post an other question.. would you mind if I tagged you for you to possibly help me out?

OpenStudy (nikato):

But I could also tell you how they have -8 there

OpenStudy (nikato):

And yes. I will help you

OpenStudy (nikato):

x^2 -4x -12 If you factor (x-6)(x+2) ---------- x+2 The x+2 cancels out. So you're left with f(x)=x-6 And remember we said x can't be -2 because the denominator would be zero and that's a no no. So we plug that into x-6 So -2-6=-8

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