calculate the molar concentration of [OH-] given that [H3O+] to be 7.7 * 10 ^ -6 ? I am having trouble understanding how to figure this out. Any help?

Question

aaronq · Answer

There are several ways, but the easiest is knowing that the product of their concentrations equals $1.0*10^{-14}$  (i guess the units are $M^2$, and this is only at 25 celsius).

to make it clearer:  $[H_3O^+]*[OH^-]=1.0*10^{-14}$

anonymous · Answer

So I would just divide 1.0 * 10 ^ 14 by the H30+ to get the answer?

aaronq · Answer

yep, but it's $\large \sf \color{red}{-}14$

anonymous · Answer

Sorry typeo. But okay thanks! that's way easier than what my teacher was saying.