find the exact value of the following? sin195
\[\frac{ (-\sqrt{6} + \sqrt{2})}{ 4 }\]
i got -1/2\[-1/2\sqrt{2-\sqrt{3}}\]
\[\sqrt{(1-\cos(30))/2} = \sqrt{1/2(2/2 - \sqrt{3}/2}\]
you use the half angle formula
my teacher provided me with this sin20=cos^20(theta)*cos(theta) but i dont understand what do i do with it do i plug in the 195 instead?
hmm you dont have any instructions? say something like prove the identity because sin2theta = 2sincos
nope thats all that it says
well the exact value of sin(195) is \[-1/2\sqrt{2-\sqrt{3}}\]
wait nvm i read the half angle identity oops sorry
using the half angle formula we double the angle value of 195 which comes to 390
ok
since 390 is coterminal with 30 with use the value of cos(30) in the formula
the formula is \[\sqrt{(1-\cos(\theta))/2}\]
the cos of 30 is \[\sqrt{3/}2\]
what do you mean by coterminal shouldnt the 30 be negative or something
im just trying to understand it
so the formula becomes \[\sqrt{(1-\sqrt{3}/2)/2}\]
coterminal just means they are at the same spot on the unit circle
since double 195 is 390 that means it goes all the way 360 degrees and then there is another 30 degrees
ok
your angle went all the way around + 30 so its at pi/6
alright i got that part
so the cosine of 390 and 30 is the same
since your angle is 195 we use the half angle formula
ok
because 195 is hard to get an exact number for we double it which gives a good number that lands on 30degrees and just divide that by 2
but the complete formula is \[\sqrt{(1-\cos(x))/2}\]
wait so do i divide 30? by 2 or what do i divide?
let me see if i can figure out how to put fractions into the equations im kinda new to openstudy
ok thanks and i am to
ill just draw it
ok
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