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another GP problem @ganeshie8
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\[1+3^{2}+3^{4}+...+ 3^{2n}\]
how many terms are there in the series ?
it just asks you to add up to \[3^{2n}\]
lets count the number of terms again
Notice the exponents : 0, 2, 4, ... , 2n
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how many terms are they ?
2n+1
@ganeshie8
nope
0, 2, 4, ... , 2n if i divide each term by 2, the number of terms wont change, right ?
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so lets divide by 2, you get : 0, 1, 2, ... , n
how many terms are they ?
n+1
yes
and r = 3^2 as you said earlier
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use the partial sum formula : \[\rm S_k = a_1 \dfrac{r^k-1}{r-1}\]
r = 3^2 k = n+1
ok i got it thanks!!!
ive got one more sorry
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